Home / RRB Railway recruitment board vacancy / RRB Patna vacancy / RRB Patna CEN 1/2019 Jobs @ www.rrbpatna.gov.in 1039 NTPC Vacancies

RRB Patna CEN 1/2019 Jobs @ www.rrbpatna.gov.in 1039 NTPC Vacancies

RRB Patna 01/2019 Advertisement Recruitment Career Notification For Graduate & Under Graduate NTPC 1039 Posts 

RRB Patna Recruitment 2019-20: 

Railway Recruitment Board (RRB) Patna CEN 01/2019 has Released Recruitment Advertisement for NTPC 1039 Non-Technical Popular Categories (NTPC) i.e. Junior Clerk cum Typist, Accounts Clerk cum Typist, Junior Time Keeper, Trains Clerk, Commercial cum Ticket Clerk, Traffic Assistant, Goods Guard, Senior Commercial cum Ticket Clerk, Senior Clerk cum Typist, Junior Account Assistant cum Typist, Senior Time Keeper, Commercial Apprentice and Station Master in various Zonal Railways and Production Units of Indian Railways vacant. Candidates can apply in prescribed application format on or before 31-03-2019. Other Detailed Information Regarding Educational Qualifications, Age Limit, Mode of Selection, Application Fee, Exam Pattern How to Apply are given below…


Important Dates for RRB NTPC Jobs Notification:
RRB NTPC 2019 Notification: 28//02/2019
What is the last date to apply for Application Form: 31 Mar 2019
Closing Date & Time for Payment of Application Fee

 (a) Online (Net Banking/ Credit Card/ Debit Card/UPI) 05.04.2019 at 23.59 hrs.

 (b) SBI Challan 05.04.2019 at 15.00 hrs.

(c) Post Office Challan 05.04.2019 at 15.00 hrs.

Final submission of Applications 12.04.2019 at 23.59 hrs.

1st Stage Computer Based Test (CBT) Tentatively scheduled

between June to September 2019

Job Location: Patna

Notification Name: RRB NTPC Recruitment 2019
Name of an Organization:Railway Recruitment Board
What are the Jobs available on this recruitment project Are Given Below There:–
Total number of vacancies: 1039 Posts
Posts name: Graduate & Under Graduate NTPC
Commercial Apprentice: 55

Station Master: 155

Goods Guard: 211

Junior Accounts Assistant Cum Typist: 230

Senior Clerk Cum Typist: 66

Senior Commercial cum Ticket Clerk: 154

Commercial cum Ticket Clerk: 45

Accounts Clerk Cum Typist: 26

Junior Clerk cum Typist: 54, 1

Trains Clerk: 42



What is the age criteria for RRB NTPC Recruitment 2019:
Minimum Age: 18 Years
Maximum age: 30 Years
Age Relaxation as per govt rules.
Age limit as on 01-07-2019
What is the Essential Qualification for RRB NTPC:
Candidates should have qualification 10th Class, Degree
What is the Application Fee?
SC/ ST/ PwD/ Ex-S: Rs.250/-
Selection Process for RRB NTPC?
Computer Based Test
Typing Skill Test/ Computer-based Aptitude Test

Document Verification/ Medical Examination
How to Apply for RRB NTPC?
candidates can apply online through the RRB Patna Website www.rrbpatna.gov.in on or before 31 Mar 2019
Important Links for RRB NTPC Recruitment 2019
Official/ Notifications:    Click Here
Official/ Notifications:    Click Here

About RRB 


Patna Junction, station code PNBE, is a major railway station in the capital city of Patna in the Indian state of Bihar. Situated in heart of the city,[5] it is the main railway station serving Patna. It falls under the Danapur division of the East Central Railway zone of the Indian Railways. Patna Junction is one of the busiest railway stations of the country.[6]

The Patna Junction railway station is connected to most of the major cities in India by the railway network.[7] Patna lies in between New Delhi and Kolkata which is one of the busiest rail routes in India. Patna has trains running frequently to Delhi and Kolkata.[8] The city is a major railway hub and has six major stations: Patna Junction, Rajendranagar Terminal, Gulzarbagh Station, Danapur railway station, Patliputra Junction and Patna Sahib Station

About Railway Jobs

Check Also

RRB Chennai NTPC Jobs 2019-20 @ www.rrbchennai.gov.in Apply 2694 Vacancies

RRB Chennai 01/2019 Advertisement Recruitment Career Notification For NTPC 2694 Vacancies  RRB Chennai Recruitment 2019-20:    Railway …

Leave a Reply

Your email address will not be published. Required fields are marked *

2 × one =